16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T505,{"@context":"https://schema.org","@type":"Quiz","name":"Mht Cet 2025 Waves PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/mht-cet/questions/2025/physics/waves/mexfkz8r","educationalLevel":"Entrance exam preparation","about":"Mht Cet / Physics / Waves","hasPart":{"@type":"Question","name":"Mht Cet 2025 Waves PYQ with Solution","text":"Two strings ' X ' and ' Y ' of a guitar produces a beat frequency of 6 Hz . When the tension of the string ' Y ' is increased, the beat frequency is found to be 4 Hz . If the frequency of string ' X ' is 300 Hz , then the original frequency of string ' Y ' is","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"B"},"comment":{"@type":"Comment","text":"Given: String X has frequency f_X = 300 \\, \\text{Hz}. String Y’s frequency is initially f_Y (unknown). Beat frequency initially = 6 \\, \\text{Hz}. That means |f_Y - f_X| = 6. So, \\; f_Y = 300 \\pm 6 = 306\\ \\text{Hz or } 294\\ \\text{Hz}. Then the tension of string Y is increased, so its frequency increases . New beat frequency = 4 \\, \\text{Hz}. Case 1: f_Y = 306 \\, \\text{Hz}. If we increase tension, the frequency rises above 306. The difference with 300 will be larger than 6, so the beat frequency..."}}}18:T4c8,

Given:

String $X$ has frequency $f_X = 300 \, \text{Hz}$.
String $Y$’s frequency is initially $f_Y$ (unknown).
Beat frequency initially = $6 \, \text{Hz}$.

That means $|f_Y - f

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