16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T54c,{"@context":"https://schema.org","@type":"Quiz","name":"Mht Cet 2025 Simple Harmonic Motion PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/mht-cet/questions/2025/physics/simple-harmonic-motion/mfajl98c","educationalLevel":"Entrance exam preparation","about":"Mht Cet / Physics / Simple Harmonic Motion","hasPart":{"@type":"Question","name":"Mht Cet 2025 Simple Harmonic Motion PYQ with Solution","text":"A spring executes S.H.M. with mass 1 kg attached to it. The force constant of the spring is 4 \\mathrm{~N} / \\mathrm{m}. If at any instant its velocity is 20 \\mathrm{~cm} / \\mathrm{s}, the displacement at that instant is (Amplitude of S.H.M. is 0.4 m )","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"B"},"comment":{"@type":"Comment","text":"We are given: Mass m = 1 \\, \\text{kg} Spring constant k = 4 \\, \\text{N/m} Velocity at some instant v = 20 \\, \\text{cm/s} = 0.2 \\, \\text{m/s} Amplitude A = 0.4 \\, \\text{m} We need the displacement x at that instant. Step 1: Angular frequency \\omega = \\sqrt{\\frac{k}{m}} = \\sqrt{\\frac{4}{1}} = 2 \\, \\text{rad/s} Step 2: Energy conservation in SHM Total energy (constant): E = \\tfrac{1}{2} k A^2 = \\tfrac{1}{2} m \\omega^2 A^2 At displacement x and velocity v: E = \\tfrac{1}{2} m v^2 + \\tfrac{1}{2} k x^..."}}}18:T48f,

We are given:

Mass $m = 1 \, \text{kg}$
Spring constant $k = 4 \, \text{N/m}$
Velocity at some instant $v = 20 \, \text{cm/s} = 0.2 \

Simple Harmonic Motion

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