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Simple Harmonic Motion

MHT CET 2025 22nd April Morning Shift

MCQ+1 / -02025

For a particle performing S.H.M.; the total energy is ' $n$ ' times the kinetic energy, when the displacement of a particle from mean position is $\frac{\sqrt{3}}{2} \mathrm{~A}$, where A is the amplitude of S.H.M. The value of ' $n$ ' is

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