Mht Cet
Simple Harmonic Motion
MHT CET 2025 22nd April Morning Shift
MCQ+1 / -02025
For a particle performing S.H.M.; the total energy is ' $n$ ' times the kinetic energy, when the displacement of a particle from mean position is $\frac{\sqrt{3}}{2} \mathrm{~A}$, where A is the amplitude of S.H.M. The value of ' $n$ ' is
