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MHT CET 2025 23rd April Morning Shift

MCQ+2 / -02025

Let mean and standard deviation of probability distribution


$$ \begin{array}{|c|c|c|c|c|} \hline \mathrm{X}=x & -3 & 0 & 1 & \alpha \\ \hline \mathrm{P}(\mathrm{X}=x) & \frac{1}{4} & \mathrm{~K} & \frac{1}{4} & \frac{1}{3} \\ \hline \end{array} $$


be $\mu$ and $\sigma$ respectively and if $\sigma-\mu=2$ then $\sigma=$

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