Properties Of Triangles

In a triangle ABC , the sides $\mathrm{a}, \mathrm{b}, \mathrm{c}$ are such that they are the roots of the equation $x^3-11 x^2+38 x-40=0$ Then

\(\frac{\cos A}{a}+\frac{\cos B}{b}+\frac{\cos C}{c}=\)