Mht Cet
Probability
MHT CET 2025 20th April Evening Shift
MCQ+2 / -02025
A random variable $X$ takes the values $0,1,2,3$, $\qquad$ with probability
$\mathrm{P}(\mathrm{X}=x)=\mathrm{k}(x+1)\left(\frac{1}{5}\right)^x$, where k is a constant.
Then $\mathrm{P}(\mathrm{X}=0)$ is
