Mht CetProbabilityMHT CET 2025 19th April Evening ShiftMCQ+2 / -02025If $X \sim B(n, p)$ then $\frac{P(X=k)}{P(X=k-1)}=$A$\frac{\mathrm{n}-\mathrm{k}}{\mathrm{k}-1} \cdot \frac{\mathrm{p}}{\mathrm{q}}$B$\frac{n-k+1}{k+1} \cdot \frac{p}{q}$C$\frac{n+1}{k} \cdot \frac{q}{p}$D$\frac{n-k+1}{k} \cdot \frac{p}{q}$Check AnswerClear SelectionReveal AnswerShow Explanation
