16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T481,{"@context":"https://schema.org","@type":"Quiz","name":"Mht Cet 2025 Parabola PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/mht-cet/questions/2025/mathematics/parabola/mexfkrkw","educationalLevel":"Entrance exam preparation","about":"Mht Cet / Mathematics / Parabola","hasPart":{"@type":"Question","name":"Mht Cet 2025 Parabola PYQ with Solution","text":"Angle between the parabola y^2=4(x-1) and x^2+4(y-3)=0 at the common end of their latus rectum is","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"A"},"comment":{"@type":"Comment","text":"For y^2=4(x-1) \\Rightarrow End of the latus rectum are (2,2),(2,-2) Similarly, For x^2+4(y-3)=0 End of the latus rectum are (-2,2),(2,2) \\therefore \\quad Common end of their latus rectum is (2,2) Consider, y^2=4(x-1) Differentiate w.r.t ' x ' 2 y \\frac{\\mathrm{~d} y}{\\mathrm{~d} x}=4(1-0) \\begin{aligned} & \\frac{\\mathrm{d} y}{\\mathrm{~d} x}=\\frac{4}{2 y} \\\\ & \\left(\\frac{\\mathrm{~d} y}{\\mathrm{~d} x}\\right)_{\\mathrm{at}(2,2)}=1 \\\\ \\therefore \\quad & \\mathrm{~m}_1=1 \\end{aligned} Consider, x^2+4..."}}}18:T453,

For $y^2=4(x-1)$

$\Rightarrow$ End of the latus rectum are $(2,2),(2,-2)$

Similarly,

For $x^2+4(y-3)=0$

End of the latus rectum are $(-2,2),(2,2)$

$\therefore \quad$ Common end of their latus rectum is $(2,2)$

Consider,

$y^2=4(x-1)$

Differentiate w.r.t ' $x$ '

$2 y \frac{\mathrm{~d} y}{\mathrm{~d} x}=4(1-0)$

$$ \

Parabola

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