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Limits Continuity And Differentiability

MHT CET 2025 22nd April Evening Shift

MCQ+2 / -02025

If $f(x)=\left\{\begin{array}{cc}\frac{1-\cos 4 x}{x^2} & , \text { if } x<0 \\ \frac{a}{\sqrt{x}} & , \text { if } x=0 \\ \frac{(16+\sqrt{x})^{\frac{1}{2}}-4}{16} & , \text { if } x>0\end{array}\right.$


is continuous at $x=0$, then $\mathrm{a}=$

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