Mht Cet
Limits Continuity And Differentiability
MHT CET 2025 20th April Morning Shift
MCQ+2 / -02025
\(\mathop {\lim }\limits_{x \to 0} \frac{\mathrm{e}^{\tan x}-\mathrm{e}^x}{\tan x-x}=\)
Mht Cet
MHT CET 2025 20th April Morning Shift
\(\mathop {\lim }\limits_{x \to 0} \frac{\mathrm{e}^{\tan x}-\mathrm{e}^x}{\tan x-x}=\)