Mht Cet
Limits Continuity And Differentiability
MHT CET 2025 19th April Evening Shift
MCQ+2 / -02025
If $\mathrm{f}(x)=\frac{(27-2 x)^{\frac{1}{3}}-3}{9-3(243+5 x)^{\frac{1}{5}}}, x \neq 0$ is continuous at $x=0$, then the value of $\mathrm{f}(0)$ is
