Mht CetIndefinite IntegrationMHT CET 2025 25th April Morning ShiftMCQ+2 / -02025\(\int \frac{1}{\mathrm{e}^x+1} \mathrm{~d} x=\)A $x+\log \left(\mathrm{e}^x+1\right)+\mathrm{c}$, where c is the constant of integration.B $x-\log \left(\mathrm{e}^x+1\right)+\mathrm{c}$, where c is the constant of integration.C $\log \left(\mathrm{e}^x-1\right)+x+\mathrm{c}$, where c is the constant of integration.D $\log \left(\mathrm{e}^{\mathrm{x}}-1\right)-x+\mathrm{c}$, where c is the constant of integration.Check AnswerClear SelectionReveal AnswerShow Explanation
