Mht CetIndefinite IntegrationMHT CET 2025 23rd April Evening ShiftMCQ+2 / -02025\(\int \sqrt{x^2+3 x} d x=\)A$\sqrt{x^2+3 x}+\log \sqrt{x^2+3 x}+c$, where c is the constant of integration.B$\frac{2 x+3}{4} \sqrt{x^2+3 x}-\frac{9}{8} \log \left(x+\sqrt{x^2+3 x}\right)+c$, where c is the constant of integration.C$x \sqrt{x^2+3 x}+\log \left(x+\sqrt{x^2+3 x}\right)+\mathrm{c}$, where c is the constant of integration.D$x+3 \sqrt{x^2+3 x}+\frac{3}{2} \log \left(x+\sqrt{x^2+3 x}\right)+\mathrm{c}$, where c is the constant of integration.Check AnswerClear SelectionReveal AnswerShow Explanation