Mht CetIndefinite IntegrationMHT CET 2025 23rd April Morning ShiftMCQ+2 / -02025\(\int\left(\frac{x-3}{x^2+9}\right)^2 d x=\)A $\frac{1}{3} \tan ^{-1}\left(\frac{x}{3}\right)-\frac{3}{x^2+9}+\mathrm{c}$, where c is the constant of integration.B $\frac{1}{3} \tan ^{-1}\left(\frac{x}{3}\right)-\frac{1}{x^2+9}+c$, where $c$ is the constant of integration.C $\frac{1}{3} \tan ^{-1}\left(\frac{x}{3}\right)+\frac{3}{x^2+9}+c$, where $c$ is the constant of integration.D $\frac{1}{3} \tan ^{-1}\left(\frac{x}{3}\right)-\frac{1}{x^2+9}+c$, where $c$ is the constant of integration.Check AnswerClear SelectionReveal AnswerShow Explanation
