Mht CetIndefinite IntegrationMHT CET 2025 21st April Morning ShiftMCQ+2 / -02025$\int \sqrt{x^2-6 x-16} \mathrm{~d} x$ equalsA$\left(\frac{x-3}{2}\right) \sqrt{x^2-6 x-16} +\frac{5}{2} \log \left(x-3+\sqrt{x^2-6 x-16}\right)+c$where c is the constant of integrationB$$ \begin{aligned} & \left(\frac{x-3}{2}\right) \sqrt{x^2-6 x-16} -\frac{25}{2} \log \left(x-3+\sqrt{x^2-6 x-16}\right)+c \end{aligned} $$where c is the constant of integrationC$\left(\frac{x-3}{2}\right) \sqrt{x^2-6 x-16}+\frac{25}{2} \log \left(x-3+\sqrt{x^2-6 x-16}\right)+c $where c is the constant of integrationD$$ \begin{aligned} \left(\frac{x-3}{2}\right) \sqrt{x^2-6 x-16} & -\frac{5}{2} \log \left(x-3+\sqrt{x^2-6 x-16}\right)+c \end{aligned} $$where $c$ is the constant of integrationCheck AnswerClear SelectionReveal AnswerShow Explanation
