Mht CetIndefinite IntegrationMHT CET 2025 20th April Evening ShiftMCQ+2 / -02025\(\int \frac{\mathrm{e}^{\tan ^{-1} 2 x}}{1+4 x^2}=\)A $4 \mathrm{e}^{\tan ^{-1} 2 x}+\mathrm{c}$, where c is the constant of integrationB $\mathrm{e}^{\tan ^{-1} 2 x}+\mathrm{c}$, where c is the constant of integrationC $\frac{\mathrm{e}^{\tan ^{-1} 2 x}}{2}+\mathrm{c}$, where c is the constant of integrationD $2 \mathrm{e}^{\tan ^{-1} 2 x}+\mathrm{c}$, where c is the constant of integrationCheck AnswerClear SelectionReveal AnswerShow Explanation
