Mht Cet
Differentiation
MHT CET 2025 25th April Morning Shift
MCQ+2 / -02025
If $\frac{x^2}{\mathrm{a}^2}+\frac{y^2}{\mathrm{~b}^2}=1$, then $\frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}$ is
Mht Cet
MHT CET 2025 25th April Morning Shift
If $\frac{x^2}{\mathrm{a}^2}+\frac{y^2}{\mathrm{~b}^2}=1$, then $\frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}$ is