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Differentiation

MHT CET 2025 25th April Morning Shift

MCQ+2 / -02025

If $\frac{x^2}{\mathrm{a}^2}+\frac{y^2}{\mathrm{~b}^2}=1$, then $\frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}$ is

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