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Differentiation

MHT CET 2025 21st April Evening Shift

MCQ+2 / -02025

If $y=\mathrm{a}^x \cdot \mathrm{~b}^{2 x-1}$, then $\frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}$ is equal to

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