Mht Cet
Differential Equations
MHT CET 2025 25th April Morning Shift
MCQ+2 / -02025
The solution of the equation $x^2 y-x^3 \frac{\mathrm{~d} y}{\mathrm{~d} x}=y^4 \cos x$, where $y(0)=1$, is
Mht Cet
MHT CET 2025 25th April Morning Shift
The solution of the equation $x^2 y-x^3 \frac{\mathrm{~d} y}{\mathrm{~d} x}=y^4 \cos x$, where $y(0)=1$, is