16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T47b,{"@context":"https://schema.org","@type":"Quiz","name":"Mht Cet 2025 Solid State PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/mht-cet/questions/2025/chemistry/solid-state/meujccte","educationalLevel":"Entrance exam preparation","about":"Mht Cet / Chemistry / Solid State","hasPart":{"@type":"Question","name":"Mht Cet 2025 Solid State PYQ with Solution","text":"Calculate the volume of unit cell having atomic radius 141.4 pm forming fcc unit cell.","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"C"},"comment":{"@type":"Comment","text":"For a face-centered cubic (fcc) unit cell, the relation between the edge length (a) and atomic radius (r) is: a = 2\\sqrt{2}r Given, r = 141.4 pm. Let's calculate step by step: Find the edge length a: a = 2\\sqrt{2} \\times 141.4\\,\\text{pm} \\sqrt{2} \\approx 1.414 a = 2 \\times 1.414 \\times 141.4 a = 2 \\times 1.414 \\times 141.4 = 2 \\times 200.04 = 400.08~\\text{pm} So, a = 400.08~\\text{pm} Convert a to cm: 1\\,\\text{pm} = 10^{-12}\\,\\text{m} = 10^{-10}\\,\\text{cm} a = 400.08 \\times 10^{-10}~\\text{cm} Fi..."}}}18:T52f,

For a face-centered cubic (fcc) unit cell, the relation between the edge length $(a)$ and atomic radius $(r)$ is:

$$ a = 2\sqrt{2}r $$

Given, $r = 141.4$ pm.

Let's calculate step by step:

Find the edge length $a$:

$$ a = 2\sqrt{2} \times 141.4\,\text{pm} $$

$$ \sqrt{2} \approx 1.414 $$

$$ a = 2 \tim

Solid State

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