16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T4df,{"@context":"https://schema.org","@type":"Quiz","name":"Mht Cet 2024 Waves PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/mht-cet/questions/2024/physics/waves/m4v5wwt3","educationalLevel":"Entrance exam preparation","about":"Mht Cet / Physics / Waves","hasPart":{"@type":"Question","name":"Mht Cet 2024 Waves PYQ with Solution","text":"A string has mass per unit length of 10^{-6} \\mathrm{~kg} / \\mathrm{cm} The equation of simple harmonic wave produced in it is \\mathrm{Y}=0.2 \\sin (2 \\mathrm{x}+80 \\mathrm{t}) \\mathrm{m}. The tension in the string is","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"A"},"comment":{"@type":"Comment","text":"The tension in the string can be determined using the formula for wave velocity, which is: v = \\sqrt{\\frac{T}{\\mu}} From this, we can express the tension T in terms of wave velocity v and mass per unit length \\mu : T = v^2 \\mu Given that: \\mu = 10^{-6} \\, \\text{kg/cm} = 10^{-4} \\, \\text{kg/m} Substituting into the tension formula, we have: T = v^2 \\times 10^{-4} \\tag{Equation (i)} The wave equation given is: Y = 0.2 \\sin(2x + 80t) To compare this with the standard form of a wave equation: y = A..."}}}18:T46e,

The tension in the string can be determined using the formula for wave velocity, which is:

$ v = \sqrt{\frac{T}{\mu}} $

From this, we can express the tension $ T $ in terms of wave velocity $ v $ and mass per unit length $ \mu $:

$ T = v^2 \mu $

Given that:

Waves

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