16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T4d2,{"@context":"https://schema.org","@type":"Quiz","name":"Mht Cet 2024 Waves PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/mht-cet/questions/2024/physics/waves/m3txgglw","educationalLevel":"Entrance exam preparation","about":"Mht Cet / Physics / Waves","hasPart":{"@type":"Question","name":"Mht Cet 2024 Waves PYQ with Solution","text":"Velocity of sound waves in air is 330 \\mathrm{~m} / \\mathrm{s}. For a particular sound wave in air, path difference of 40 cm is equivalent to phase difference of 1.6 \\pi. The frequency of this wave is","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"C"},"comment":{"@type":"Comment","text":"The frequency of a wave can be determined using the relationship between phase difference, path difference, and wavelength. Given: Phase difference, \\Delta \\phi = 1.6 \\pi Path difference, \\Delta x = 40 \\text{ cm} = 0.4 \\text{ m} Velocity of sound in air, v = 330 \\text{ m/s} The phase difference is related to the path difference by the formula: \\Delta \\phi = \\frac{2\\pi}{\\lambda} \\Delta x where \\lambda is the wavelength. Rearranging the formula to solve for \\lambda: \\lambda = \\frac{2\\pi}{\\Delta \\..."}}}18:T496,

The frequency of a wave can be determined using the relationship between phase difference, path difference, and wavelength.

Given:

Phase difference, $$\Delta \phi = 1.6 \pi$$

Path difference, $$\Delta x = 40 \text{ cm} = 0.4 \text{ m}$$

Velocity of sound i

Waves

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