16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T4dc,{"@context":"https://schema.org","@type":"Quiz","name":"Mht Cet 2024 Fluid Mechanics PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/mht-cet/questions/2024/physics/fluid-mechanics/m44hbzja","educationalLevel":"Entrance exam preparation","about":"Mht Cet / Physics / Fluid Mechanics","hasPart":{"@type":"Question","name":"Mht Cet 2024 Fluid Mechanics PYQ with Solution","text":"The pressure inside two soap bubbles, (A) is 1.01 and that of (B) is 1.02 atmosphere respectively. The ratio of their respective radii (A to B) is (outside pressure =1 \\mathrm{~atm}.)","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"A"},"comment":{"@type":"Comment","text":"The pressure inside a soap bubble can be described by the formula: P = P_0 + \\frac{4T}{r} where: P is the internal pressure of the bubble, P_0 is the external (atmospheric) pressure, T is the surface tension of the soap solution, r is the radius of the bubble. Given: For bubble A: P_A = 1.01 \\, \\text{atm} For bubble B: P_B = 1.02 \\, \\text{atm} P_0 = 1 \\, \\text{atm} Using the formula for pressure inside a bubble, we have: For bubble A: 1.01 = 1 + \\frac{4T}{r_A} Simplifying, \\frac{4T}{r_A} = 0.01..."}}}18:T475,

The pressure inside a soap bubble can be described by the formula:

$$ P = P_0 + \frac{4T}{r} $$

where:

$ P $ is the internal pressure of the bubble,

$ P_0 $ is the external (atmospheric) pressure,

$ T $ is the surface tension of the soap so

Fluid Mechanics

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