Mht Cet

Probability

MHT CET 2024 15th May Evening Shift

MCQ+2 / -02024

Suppose three coins are tossed simultaneously. If $X$ denotes the number of heads, then probability distribution of x is

$X=x$	0	1	2	3
$P(X=x)$	$\frac{2}{8}$	$\frac{2}{8}$	$\frac{3}{8}$	$\frac{1}{8}$

$X=x$	0	1	2	3
$P(X=x)$	$\frac{1}{8}$	$\frac{3}{8}$	$\frac{3}{8}$	$\frac{1}{8}$

$X=x$	0	1	2
$P(X=x)$	$\frac{3}{8}$	$\frac{3}{8}$	$\frac{2}{8}$

$X=x$	0	1	2	3
$P(X=x)$	$\frac{1}{8}$	$\frac{1}{8}$	$\frac{3}{8}$	$\frac{3}{8}$

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