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Mht Cet

Probability

MHT CET 2024 3rd May Evening Shift

MCQ+2 / -02024

For the probability distribution



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$\mathrm{X:}$ $-2$ $-1$ $0$ $1$ $2$ $3$
$\mathrm{p}(x):$ 0.1 0.2 0.2 0.3 0.15 0.05


Then the $\operatorname{Var}(\mathrm{X})$ is


(Given : \(\left.(0.25)^2=0.0625,(0.35)^2=0.1225,(0.45)^2=0.2025\right)\)

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