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Inverse Trigonometric Functions

MHT CET 2024 4th May Evening Shift

MCQ+2 / -02024

\(\frac{\mathrm{d}}{\mathrm{~d} x}\left(\cos ^{-1}\left(\frac{x-\frac{1}{x}}{x+\frac{1}{x}}\right)\right)=\)

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