Fluid Mechanics

Consider a soap film on a rectangular frame of wire of area \(3 \times 3 \mathrm{~cm}^2\). If the area of the soap film is increased to \(5 \times 5 \mathrm{~cm}^2\), the work done in the process will be (surface tension of soap solution is \(\left.2.5 \times 10^{-2} \mathrm{~N} / \mathrm{m}\right)\)