Mht Cet
Circular Motion
MHT CET 2023 9th May Evening Shift
MCQ+1 / -02023
A simple pendulum of length \(2 \mathrm{~m}\) is given a horizontal push through angular displacement of \(60^{\circ}\). If the mass of bob is 200 gram, the angular velocity of the bob will be (Take Acceleration due to gravity \(=10 \mathrm{~m} / \mathrm{s}^2\) ) \(\left(\sin 30^{\circ}=\cos 60^{\circ}=0.5, \cos 30^{\circ}=\sin 60^{\circ}=\sqrt{3} / 2\right)\)
