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Mht Cet

Circular Motion

MHT CET 2023 9th May Evening Shift

MCQ+1 / -02023

A simple pendulum of length \(2 \mathrm{~m}\) is given a horizontal push through angular displacement of \(60^{\circ}\). If the mass of bob is 200 gram, the angular velocity of the bob will be (Take Acceleration due to gravity \(=10 \mathrm{~m} / \mathrm{s}^2\) ) \(\left(\sin 30^{\circ}=\cos 60^{\circ}=0.5, \cos 30^{\circ}=\sin 60^{\circ}=\sqrt{3} / 2\right)\)

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