Three Dimensional Geometry

Consider the lines \(\mathrm{L}_1: \frac{x+1}{3}=\frac{y+2}{1}=\frac{\mathrm{z}+1}{2}\)

\(\mathrm{L}_2: \frac{x-2}{1}=\frac{y+2}{2}=\frac{\mathrm{z}-3}{3}\), then the unit vector perpendicular to both \(\mathrm{L}_1\) and \(\mathrm{L}_2\) is