Mht Cet
Limits Continuity And Differentiability
MHT CET 2023 14th May Evening Shift
MCQ+2 / -02023
Let \(\mathrm{f}(x)=5-|x-2|\) and \(\mathrm{g}(x)=|x+1|, x \in \mathrm{R}\) If \(\mathrm{f}(x)\) attains maximum value at \(\alpha\) and \(\mathrm{g}(x)\) attains minimum value at \(\beta\), then \(\lim _\limits{x \rightarrow-\alpha \beta} \frac{(x-1)\left(x^2-5 x+6\right)}{x^2-6 x+8}\) is equal to
