Mht CetIndefinite IntegrationMHT CET 2023 12th May Evening ShiftMCQ+2 / -02023\(\int \frac{1}{(x+2)(1+x)^2} d x\) has the valueA\(2 \log \left(\frac{x+2}{x^2+1}\right)+4 \tan ^{-1} x+\mathrm{c}\), where \(\mathrm{c}\) is a constant of integration.B\(\log \frac{x+2}{x^2+1}-4 \tan ^{-1} x+\mathrm{c}\), where \(\mathrm{c}\) is a constant of integration.C\(\log \frac{(x+2)^2}{\left(x^2+1\right)}+4 \tan ^{-1} x+c\), where c is a constant of integration.DNoneCheck AnswerClear SelectionReveal AnswerShow Explanation
