Mht Cet
Differentiation
MHT CET 2023 14th May Evening Shift
MCQ+2 / -02023
If \(x=\sqrt{\mathrm{e}^{\sin ^{-1} t}}\) and \(y=\sqrt{\mathrm{e}^{\cos ^{-1} t}}\), then \(\frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}\) is
Mht Cet
MHT CET 2023 14th May Evening Shift
If \(x=\sqrt{\mathrm{e}^{\sin ^{-1} t}}\) and \(y=\sqrt{\mathrm{e}^{\cos ^{-1} t}}\), then \(\frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}\) is