Mht Cet
Differentiation
MHT CET 2023 12th May Morning Shift
MCQ+2 / -02023
\(y=(1+x)\left(1+x^2\right)\left(1+x^4\right) \ldots \ldots \ldots\left(1+x^{2 n}\right)\),
then the value of \(\frac{\mathrm{d} y}{\mathrm{~d} x}\) at \(x=0\) is
Mht Cet
MHT CET 2023 12th May Morning Shift
\(y=(1+x)\left(1+x^2\right)\left(1+x^4\right) \ldots \ldots \ldots\left(1+x^{2 n}\right)\),
then the value of \(\frac{\mathrm{d} y}{\mathrm{~d} x}\) at \(x=0\) is