Mht Cet
Differentiation
MHT CET 2023 9th May Morning Shift
MCQ+2 / -02023
If \(x^2+y^2=\mathrm{t}+\frac{1}{\mathrm{t}}\) and \(x^4+y^4=\mathrm{t}^2+\frac{1}{\mathrm{t}^2}\), then \(\frac{\mathrm{d} y}{\mathrm{~d} x}\) is equal to
Mht Cet
MHT CET 2023 9th May Morning Shift
If \(x^2+y^2=\mathrm{t}+\frac{1}{\mathrm{t}}\) and \(x^4+y^4=\mathrm{t}^2+\frac{1}{\mathrm{t}^2}\), then \(\frac{\mathrm{d} y}{\mathrm{~d} x}\) is equal to