Mht CetDifferential EquationsMHT CET 2023 13th May Evening ShiftMCQ+2 / -02023The solution of \((1+x y) y d x+(1-x y) x d y=0\) isA\(\log \left(\frac{x}{y}\right)+\frac{1}{x y}=k\), where \(k\) is constant of integrationB\(\log \left(\frac{x}{y}\right)=\frac{1}{x y}+k\), where \(k\) is constant of integrationC\(\log \left(\frac{x}{y}\right)+{x y}=k\), where \(k\) is constant of integrationD\(\log \left(\frac{x}{y}\right)={x y}+k\), where \(k\) is constant of integrationCheck AnswerClear SelectionReveal AnswerShow Explanation
