Liquid Solution

Calculate the amount of solute dissolved in 160 gram solvent that boils at \(85^{\circ} \mathrm{C}\), the molar mass of solute is \(120 \mathrm{~g} \mathrm{~mol}^{-1}\).
\(\left(\mathrm{K}_{\mathrm{b}}\right.\) for solvent \(=2.7^{\circ} \mathrm{C} \mathrm{~kg} \mathrm{~mol}^{-1}\) and boiling point of solvent \(=76^{\circ} \mathrm{C}\))