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Dual Nature Of Radiation

MHT CET 2021 22th September Morning Shift

MCQ+1 / -02021

Kinetic energy of a proton is equal to energy '\(E\)' of a photon. Let '\(\lambda_1\)' be the de-Broglie wavelength of proton and '\(\lambda_2\)' is the wavelength of photon. If \(\frac{\lambda_1}{\lambda_2} \alpha E^n\), then the value of '\(n\)' is

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