Mht CetIonic EquilibrumMHT CET 2021 21th September Evening ShiftMCQ+1 / -02021The pH of 0.005 M KOH is 9.95. Calculate the [OH\(^-\)] ?A6.71 \(\times\) 10\(^{-4}\) MB1.12 \(\times\) 10\(^{-4}\) MC4.45 \(\times\) 10\(^{-5}\) MD8.91 \(\times\) 10\(^{-5}\) MCheck AnswerClear SelectionReveal AnswerShow Explanation
