Mht Cet
Differential Equations
MHT CET 2020 19th October Evening Shift
MCQ+2 / -02020
The general solution of the differential equation $\left(1+y^2\right)+\left(x-e^{\tan ^{-1} y}\right) \frac{d y}{d x}=0$ is
Mht Cet
MHT CET 2020 19th October Evening Shift
The general solution of the differential equation $\left(1+y^2\right)+\left(x-e^{\tan ^{-1} y}\right) \frac{d y}{d x}=0$ is