16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T49b,{"@context":"https://schema.org","@type":"Quiz","name":"Mht Cet 2019 Waves PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/mht-cet/questions/2019/physics/waves/m2txx69n","educationalLevel":"Entrance exam preparation","about":"Mht Cet / Physics / Waves","hasPart":{"@type":"Question","name":"Mht Cet 2019 Waves PYQ with Solution","text":"A stretched wire of length 260 cm is set into vibrations. It is divided into three segments whose frequencies are in the ratio 2: 3: 4. Their lengths must be","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"B"},"comment":{"@type":"Comment","text":"The frequency produced by a stretched wire is determined by the equation: f = \\frac{p}{2l} \\sqrt{\\frac{T}{m}} \\quad\\text{.... (i)} where: p is the number of loops formed in vibration, l is the length of the wire, T is the tension in the wire, m is the mass per unit length of the wire. From equation (i), it follows that: f \\propto \\frac{1}{l} Given that the ratio of frequencies of the three segments is 2:3:4 , we can deduce: \\begin{aligned} & f_1: f_2: f_3 = 2: 3: 4 \\\\ & \\Rightarrow l_1: l_2: l_..."}}}18:T416,

The frequency produced by a stretched wire is determined by the equation:

$ f = \frac{p}{2l} \sqrt{\frac{T}{m}} \quad\text{.... (i)} $

where:

$ p $ is the number of loops formed in vibration,

$ l $ is the length of the wire,

$ T $ is the tension in the wire,

$ m $ is the mass per unit lengt

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