Mht Cet
Inverse Trigonometric Functions
MHT CET 2019 2nd May Morning Shift
MCQ+2 / -02019
If $f(x)=\cos ^{-1}\left[\frac{1-(\log x)^2}{1+(\log x)^2}\right]$, then $f^{\prime}(e)=\ldots$
Mht Cet
MHT CET 2019 2nd May Morning Shift
If $f(x)=\cos ^{-1}\left[\frac{1-(\log x)^2}{1+(\log x)^2}\right]$, then $f^{\prime}(e)=\ldots$