Mht CetIndefinite IntegrationMHT CET 2019 2nd May Morning ShiftMCQ+2 / -02019\(\int \frac{1}{\left(x^2+1\right)^2} d x=\ldots\)A $\tan ^{-1} x-\frac{1}{2 x\left(x^2+1\right)}+c$B $\frac{1}{2} \tan ^{-1} x+\frac{x}{2\left(x^2+1\right)}+c$C $\tan ^{-1} x+\frac{1}{x^2+1}+c$D $\tan ^{-1} x+\frac{1}{2\left(x^2+1\right)}+c$Check AnswerClear SelectionReveal AnswerShow Explanation
