Kcet
Differential Equations
KCET 2025
MCQ+1 / -02025
If ' $a$ ' and ' $b$ ' are the order and degree respectively of the differentiable equation. $\left(\frac{d^2 y}{d x^2}\right)^2+\left(\frac{d y}{d x}\right)^3+x^4=0$, then $a-b=$ $\qquad$
Kcet
KCET 2025