16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T4df,{"@context":"https://schema.org","@type":"Quiz","name":"Kcet 2021 Circular Motion PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/kcet/questions/2021/physics/circular-motion/ltd1csma","educationalLevel":"Entrance exam preparation","about":"Kcet / Physics / Circular Motion","hasPart":{"@type":"Question","name":"Kcet 2021 Circular Motion PYQ with Solution","text":"A coin placed on a rotating turn table just slips if it is placed at a distance of 4 \\mathrm{~cm} from the centre. If the angular velocity of the turn table is doubled it will just slip at a distance of","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"A"},"comment":{"@type":"Comment","text":"When a coin is placed on a rotating turntable and is about to slip, the necessary centripetal force for maintaining its rotation is provided by friction. This relationship can be expressed as: m r \\omega^2 = \\mu m g where: m is the mass of the coin, r is the distance of the coin from the center of the turntable, \\omega is the angular velocity of the turntable, \\mu is the coefficient of friction, and g is the acceleration due to gravity. Since m , \\mu , and g are constant, the equation can be si..."}}}18:T48c,

When a coin is placed on a rotating turntable and is about to slip, the necessary centripetal force for maintaining its rotation is provided by friction. This relationship can be expressed as:

$ m r \omega^2 = \mu m g $

where:

$ m $ is the mass of the coin,

Circular Motion

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