>$$ v = 3600 \, \text{km/hr} = \frac{3600 \times 1000 \, \text{m}}{3600 \, \text{s}} = 1000 \, \text{m/s} $$

The Earth's magnetic field at the location is $$B = 4 \times 10^{-4} \, \text{T}.$$

The dip angle is $$30^\circ,$$ meaning the magnetic field makes an angle of $$30^\circ$$ with the horizontal. Hence, the vertical (downward) component of the magnetic field is:

$$ B_v = B \sin(30^\circ) = 4 \times 10^{-4} \times \frac{1}{2} = 2 \times 10^{-4} \, \text{T}. $$

In such problems, the induced motional emf (electromotive force) for a conductor of length $$L$$ moving through a magnetic field is given by:

$$ \epsilon = B_{\perp} \, v \, L, $$

where $$B_{\perp}$$ is the component of the magnetic field perpendicular to the conductor.

Here, the jet is traveling East, and it is typically assumed that the plane’s wings are oriented North-South. Therefore, only the vertical component $$B_v$$ contributes to the potential difference across the wings.

Using the values:

$$v = 1000 \, \text{m/s}$$

$$L = 25 \, \text{m}$$

$$B_v = 2 \times 10^{-4} \, \text{T},$$

The induced emf is:

$$ \epsilon = v \, L \, B_v = 1000 \times 25 \times 2 \times 10^{-4} \, \text{V}. $$

Compute the value:

First, multiply $$1000 \times 25 = 25000.$$

Then, multiply $$25000 \times 2 \times 10^{-4} = 25000 \times 0.0002 = 5 \, \text{V}.$$

Thus, the potential difference between the ends of the wing is $$5 \, \text{V},$$ which corresponds to Option B.

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