16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T4b6,{"@context":"https://schema.org","@type":"Quiz","name":"Kcet 2018 Gravitation PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/kcet/questions/2018/physics/gravitation/m7isfer1","educationalLevel":"Entrance exam preparation","about":"Kcet / Physics / Gravitation","hasPart":{"@type":"Question","name":"Kcet 2018 Gravitation PYQ with Solution","text":"A space station is at a height equal to the radius of the Earth. If ' v_E ' is the escape velocity on the surface of the Earth, the same on the space station is \\qquad times v_E.","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"C"},"comment":{"@type":"Comment","text":"To solve the problem, follow these steps: The escape velocity is given by the formula: v = \\sqrt{\\frac{2GM}{r}} where: G is the gravitational constant, M is the mass of the Earth, r is the distance from the center of the Earth. On the Earth's surface, where r = R (Earth's radius), the escape velocity is: v_E = \\sqrt{\\frac{2GM}{R}} For a space station at a height equal to the Earth's radius, the distance from the center is: r = R + R = 2R So, the escape velocity at the space station is: v_{stati..."}}}18:T45c,

To solve the problem, follow these steps:

The escape velocity is given by the formula:

$$v = \sqrt{\frac{2GM}{r}}$$

where:

$$G$$ is the gravitational constant,

$$M$$ is the mass of the Earth,

$$r$$ is the distance from the center of the Earth.

Gravitation

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