16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T501,{"@context":"https://schema.org","@type":"Quiz","name":"Kcet 2017 Work Energy And Power PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/kcet/questions/2017/physics/work-energy-and-power/m9duqx48","educationalLevel":"Entrance exam preparation","about":"Kcet / Physics / Work Energy And Power","hasPart":{"@type":"Question","name":"Kcet 2017 Work Energy And Power PYQ with Solution","text":"A motor pump lifts 6 tonnes of water from a well of depth 25 m to the first floor of height 35 m from the ground floor in 20 minutes. The power of the pump (in kW ) is \\left[g=10 \\mathrm{~ms}^{-2}\\right. ]","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"A"},"comment":{"@type":"Comment","text":"Given: Water lifted: 6 tonnes (6000 kg) Depth of well: 25 m Height of first floor: 35 m Time taken: 20 minutes (or 1200 seconds) Gravitational acceleration: g = 10 \\, \\text{m/s}^2 To find the power of the pump: Calculate the work done: The work done in lifting the water is given by the formula: \\text{Work} = m \\times g \\times h Here, h is the height difference from the well to the first floor, which is 35 \\text{ m} - 25 \\text{ m} = 10 \\text{ m} . Substitute the values: \\text{Work} = 6000 \\times..."}}}18:T47c,

Given:

Water lifted: 6 tonnes (6000 kg)

Depth of well: 25 m

Height of first floor: 35 m

Time taken: 20 minutes (or 1200 seconds)

Gravitational acceleration: $ g = 10 \, \text{m/s}^2 $

Work Energy And Power

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