16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T502,{"@context":"https://schema.org","@type":"Quiz","name":"Kcet 2017 Motion In A Straight Line PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/kcet/questions/2017/physics/motion-in-a-straight-line/m9durank","educationalLevel":"Entrance exam preparation","about":"Kcet / Physics / Motion In A Straight Line","hasPart":{"@type":"Question","name":"Kcet 2017 Motion In A Straight Line PYQ with Solution","text":"A car moving with a velocity of 20 \\mathrm{~ms}^{-1} stopped at a distance of 40 m . If the same car is travelling at double the velocity, the distance travelled by it for same retardation is","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"C"},"comment":{"@type":"Comment","text":"Given Initial Conditions : Initial velocity, u = 20 \\, \\mathrm{m/s} Stopping distance, s = 40 \\, \\mathrm{m} Determine Retardation (Deceleration) : We use the equation from Newton's second law of motion: v^2 = u^2 + 2as Since the car stops, its final velocity v = 0 . Therefore, we have: 0^2 - u^2 = 2 \\times a \\times s Substituting the given values: 0 - 20^2 = 2 \\times a \\times 40 -400 = 80a Solving for a : a = \\frac{-400}{80} = -5 \\, \\mathrm{m/s^2} Increased Velocity Condition : When the velocit..."}}}18:T4bd,

Given Initial Conditions:

Initial velocity, $ u = 20 \, \mathrm{m/s} $

Stopping distance, $ s = 40 \, \mathrm{m} $

Determine Retardation (Deceleration):

We use the equation

Motion In A Straight Line

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