16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T4e7,{"@context":"https://schema.org","@type":"Quiz","name":"Kcet 2017 Electrostatics PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/kcet/questions/2017/physics/electrostatics/m9dur52a","educationalLevel":"Entrance exam preparation","about":"Kcet / Physics / Electrostatics","hasPart":{"@type":"Question","name":"Kcet 2017 Electrostatics PYQ with Solution","text":"4 \\times 10^{10} electrons are removed from a neutral metal sphere of diameter 20 cm placed in air. The magnitude of the electric field (in \\mathrm{NC}^{-1} ) at a distance of 20 cm from its centre is","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"D"},"comment":{"@type":"Comment","text":"Given the following parameters: Number of electrons removed (n): 4 \\times 10^{10} **Diameter of the sphere (D):** \\(20 \\, \\text{cm} **Radius of the sphere (r):** \\(\\frac{20}{2} = 10 \\, \\text{cm} = 0.1 \\, \\text{m} We need to calculate the magnitude of the electric field at a distance of 20 \\, \\text{cm} from the center of the sphere. The formula for the electric field outside the sphere is: E = \\frac{q}{4 \\pi \\varepsilon_0 r^2} = \\frac{n e}{4 \\pi \\varepsilon_0 r^2} Where: e = 1.6 \\times 10^{-19}..."}}}18:T550,

Given the following parameters:

Number of electrons removed $(n)$: $4 \times 10^{10}$

**Diameter of the sphere $(D):** \(20 \, \text{cm}$

**Radius of the sphere $(r):** \(\frac{20}{2} = 10 \, \text{cm} = 0.1 \, \text{m}$

Electrostatics

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