KcetChemical KineticsKCET 2017MCQ+1 / -02017For a reaction $\frac{1}{2} A \rightarrow 2 B$ rate of disappearance of $A$ is related to rate of appearance of $B$ by the expressionA $\frac{-d[A]}{d t}=\frac{1}{2} \frac{d[B]}{d t}$B $\frac{-d[A]}{d t}=4 \frac{d[B]}{d t}$C $\frac{-d[A]}{d t}=\frac{1}{4} \frac{d[B]}{d t}$D $\frac{-d[A]}{d t}=\frac{d[B]}{d t}$Check AnswerClear SelectionReveal AnswerShow Explanation
